Question

10^x+2=10b b>0
a)log b
b) log b+1
c)lob b-2
d)lob b+2
e)lob b-1

Answer 1

${10}^{x + 2} = 10b \\ {10}^{x} . \: {10}^{2} = 10b \\ log( {10}^{x} \: . \: {10}^{2} ) = log(10.b) \\ (log( {10}^{x}) + log( {10}^{2} )) =( log(10) + log(b)) \\( x. log(10) + 2. log(10) ) =(1 + log(b) )\\ (x \: . \: 1 + 2 \: . \: 1) = 1 + log(b) \\ x + 2 =1 + log(b) \\ x = 1 - 2 + log(b) \\ x = - 1 + log(b) \\ x = log(b) - 1$

Espero ter ajudado!!! Bons estudos!!!