Question

(10 x 10+ 4 x 11) + 12 [ (20+ 19 x 10) + 39 +15]} + 50 =



é urgente!!!​

Answer 1

$\Large\mathsf\displaystyle{}\left(10\cdot10 + 4\cdot11\right) + 12 \{\left(20 + 19\cdot10\right) + 39 + 15 \} + 50 \\\\\Large\mathsf\displaystyle{}\left(100 + 4\cdot11\right) + 12 \{\left(20 + 19\cdot10\right) + 39 + 15 \} + 50 \\\Large\mathsf\displaystyle{} \left(100 + 44\right) + 12 \{\left(20 + 19\cdot10\right) + 39 + 15 \} + 50 \\\Large\mathsf\displaystyle{} \left(100 + 44\right) + 12 \{\left(20 + 190\right) + 39 + 15 \} + 50 \\ \Large\mathsf\displaystyle{}144 + 12 \{\left(20 + 19\right) + 39 + 15 \} + 50 \\ \Large\mathsf\displaystyle{}144 + 12\left(200 + 39 + 15\right) + 50 \\ \Large\mathsf\displaystyle{}144 + 12\cdot264 + 50 \\ \Large\mathsf\displaystyle{}144 + 3168 + 50 \\ \Large\mathsf\displaystyle{}3312 + 50 \\\Large\mathsf\displaystyle{} = 3362$

Solução:

$\bm\Large\begin{gathered} \begin{gathered}\large \overline{ \boxed{\boxed{ \begin{array}{r}\mathsf{ 3362 }\end{array}}}} \end{gathered}  \end{gathered}$

$\bm\Large\begin{gathered} \begin{gathered}\large \overline{ \boxed{\boxed{ \begin{array}{r}\mathsf{\red{Bons~Estudos} }\end{array}}}} \end{gathered}  \end{gathered}$