Question

1° Resolva as equaçãos no conjunto IR
a) x²-49=0
b)16ײ-1=0

Answer 1

Resposta:

a) x²-49=0

Δ=b²-4ac

Δ= 0 -4.1.(-49)

Δ= 196

x=-b+-√Δ/2a

x=0+-√196/2.1

x=0+-13/2

x'= 0+13/2= 13/2

x''= 0-13/2= -13/2

b) 16x²-1=0

Δ= b²-4ac

Δ= 0 -4.1. (-1)

Δ= 4

x= -b+-√Δ/2a

x= 0+-√4/2.1

x=0+-2/2

x'= 0+2/2 = 2/2= 1

x''= 0-2/2= -2/2= -1

Explicação passo-a-passo: