Question

10)Racionalizar os radicais

Answer 1

Caso esteja pelo app, e tenha problemas para visualizar esta resposta, experimente abrir pelo navegador https://brainly.com.br/tarefa/41214221

                                                       

$\boxed{\begin{array}{l}\bf a)~\sf\dfrac{11}{\sqrt{11}}=\dfrac{\diagdown\!\!\!\!\!\!11\sqrt{11}}{\diagdown\!\!\!\!\!\!11}=\sqrt{11}\\\bf b)~\sf\dfrac{3}{\sqrt{5}}=\dfrac{3\sqrt{5}}{5}\\\bf c)~\sf\dfrac{8}{\sqrt{3}}=\dfrac{8\sqrt{3}}{3}\\\bf d)~\sf\dfrac{5\sqrt{2}}{\sqrt{6}}=\dfrac{5\diagdown\!\!\!\!\!\sqrt{2}}{\diagdown\!\!\!\!\!\!\sqrt{2}\cdot\sqrt{3}}=\dfrac{5\sqrt{3}}{3}\\\bf e)~\sf\dfrac{7}{2\sqrt{3}}=\dfrac{7\sqrt{3}}{2\cdot3}=\dfrac{7\sqrt{3}}{6}\end{array}}$

$\large\boxed{\begin{array}{l}\bf f)~\sf\dfrac{2\sqrt{3}}{3\sqrt{5}}=\dfrac{2\sqrt{15}}{15}\\\bf g)~\sf\dfrac{6}{\sqrt[\sf3]{\sf2}}=\dfrac{6\sqrt[\sf3]{\sf6^2}}{2}=3\sqrt[\sf3]{\sf36}\end{array}}$