Question

(10 - q) elevado a 2
(z + 6) * (z - 6)

Answer 1

Olá!

${(10 - q)}^{2} =$

${10}^{2} - 2 \times 10 \times q + {q}^{2}$

${q}^{2} - 20q + 100$

$(z + 6) \times (z - 6) =$

${z}^{2} - 6z + 6z - 36$

${z}^{2} - 36$

:)