Question

10 PONTOS PARA A RESPOSTA CERTA!!!!! báskara preciso muito dessa ajuda quem puder ajudar obrigado :D
1) x2 - 7x + 6 = 0 
a)
b)
c)
2) 2x2 -8x + 8 = 0
a)
b)
c)
3) x2 + 5x -6 = 0
a)
b)
c)
4) 3X2 + 2x - 5 = 0
a)
b)
c)
5)x2 - 10x+.24 = 0
a)
b)
c)

Answer 1

1) x² -7x +6=0
a=1  b=-7  c=6
Δ= b² -4.a.c
Δ=(-7)² -4 . 1 . 6
Δ= 49 - 24
Δ= 25
x= $\frac{-b+- \sqrt{Δ} }{2.a}$
x=$\frac{-(-7)+- \sqrt{25} }{2.1}$
x'=$\frac{7+5}{2}$
x'=$\frac{12}{2}$
x'= 6
x''=$\frac{7-5}{2}$
x''=$\frac{2}{2}$
x''= 1


2) 2x² -8x +8=0
a= 2  b= -8  c=8
Δ= b² -4.a.c
Δ=(-8)² -4 . 2 . 8
Δ=64 - 64
Δ=0
x= $\frac{-b+- \sqrt{Δ} }{2.a}$
x=$\frac{-(2)+- \sqrt{0} }{2.2}$
x'=$\frac{-2+0}{4}$
x'=$\frac{-2}{4}$
x'= -0,5
x''=$\frac{-2-0}{4}$
x''=$\frac{-2}{4}$
x''= -0,5


3) x² +5x -6=0
a= 1  b=5  c= -6
Δ= b² -4.a.c
Δ=(5)² -4 . 1 . -6
Δ= 25 + 24
Δ= 49
x= $\frac{-b+- \sqrt{Δ} }{2.a}$
x=$\frac{-(5)+- \sqrt{49} }{2.1}$
x'=$\frac{-5+7}{2}$
x'=$\frac{2}{2}$
x'= 1
x''=$\frac{-5-7}{2}$
x''=$\frac{-12}{2}$
x''= -6


4) 3x² +2x -5=0
a= 3  b= 2  c= -5
Δ= b² -4.a.c
Δ=(2)² -4 . 3 . -5
Δ= 4 + 60
Δ= 64
x= $\frac{-b+- \sqrt{Δ} }{2.a}$
x=$\frac{-(2)+- \sqrt{64} }{2.3}$
x'=$\frac{-2+8}{6}$
x'=$\frac{6}{6}$
x'=1
x''=$\frac{-2-8}{6}$
x''=$\frac{-10}{6}$
x''= 1,666...


5) x² -10x +24=0
a= 1  b= -10  c= 24
Δ= b² -4.a.c
Δ=(-10)² -4 . 1 . 24
Δ= 100 - 96
Δ= 4
x= $\frac{-b+- \sqrt{Δ} }{2.a}$
x=$\frac{-(-10)+- \sqrt{4} }{2.1}$
x'=$\frac{10+2}{2}$
x'=$\frac{12}{2}$
x'= 6
x''=$\frac{10-2}{2}$
x''=$\frac{8}{2}$
x''= 4