Question

10) Dada a função f(x) = x² - 6x – 16
valores de x, f(x)=0?
a)x' = -2ex" = -2
b)x'= -2 ex' = 8
c)x'= 0 ex'' = -1
d)x'= -1 ex'' = 0
e)x' = 8 ex'' = 8​

Answer 1

/\= b² - 4·a·c

/\= (-6)² - 4·1·(-16)

/\= 36 + 64

/\= 100

$\frac{ - b + - \sqrt{delta} }{2.a} = \frac{ 6 + - \sqrt{100} }{2.1} = \frac{ 6 + - 10}{2}$

X' =

$\frac{6 + 10}{2} = \frac{16}{2} = 8$

X'' =

$\frac{6 - 10}{2} = \frac{ - 4}{2} = - 2$

S= {8, -2}

Opção B)