Question

10. Calcule o valor de X no triângulo

11. Calcule o valor de X no quadrilátero

13.qual o valor de X

Answer 1

10)

x+x+20°+2x=180°

4x+20°=180°

4x=180°-20°

4x=160°

x=160°/4=40°

11)si=(4-2).180°=2.180°=360°

x+x+x+105°=360°

3x=360°-105°

3x=255°

x=255°/3=85°

12) d=n(n-3)/2

d=11(11-3)/2=11.8/2=11.4=44

13)si(5-2).180°=3.180°=540°

x+75°+x+x+75°=540°

3x+150°=540°

3x=540°-150°

3x=390°

x=390°/3= 130°

Answer 2

Resposta:

Explicação passo-a-passo:

10)

x+x+20°+2x=180°

4x+20°=180°

4x=180°-20°

4x=160°

x=160°/4=40°

11)si=(4-2).180°=2.180°=360°

x+x+x+105°=360°

3x=360°-105°

3x=255°

x=255°/3=85°

13)si(5-2).180°=3.180°=540°

x+75°+x+x+75°=540°

3x+150°=540°

3x=540°-150°

3x=390°