Question

10) Calcule log 24, sabendo que log 2 = a e log
3=b.
a) a + b
b) a + 3b
c) 3a + b
d) 2a + b
e) a + 2b​

Answer 1

24 = 2*2*2*3

log 24

log (2^3 * 3)

log 2^3 + log3

3*log 2 + log 3

3a + b

Answer 2

Resposta:

$log(24) = 3 log2 + log(3) = 3.a + b =$

letra C