Question

10- Calcule as operações abaixo com monômios:

a) 10bc – 12bc + 7bc – 3bc =

b) 0,9ab3 + 2,5ab3 – 5,2ab3 =

c) (-2ay2) . (2,6a) =

d) (-5a4bc3) . (b2c) . (+4a2c) =

e) (+9y6) : (-3y3) =

f) (-0,4b2c4) : (0,25bc4) =​

Answer 1

10bc-12bc+7bc-3bc=

10-12+7-3= -bc

-bc= 2  *(-1)

bc= -2

0.9ab³ + 2.5ab³ - 5.2ab³

3.4ab³ - 5.2ab³

-1.8ab³ <<<<<<

c nao faco ideia

(-5a^4bc^3).(b^2c).(4a^2c)=

-20a^6b^3c^5

=(9y×6)÷(−3y×3)

=(54y)÷(−9y)

= −6

4/10 b²c )/ ( 25/100 bc )

-4/10 : 25/100 = - 4/10 * 100/25 = - 400/250 -40/25 =- 8/5 **

b²c / bc = b

resposta - 8/5b ***

espero ter ajudado