Question

10×2-11×+1=0
Eezouva a e quasao

Answer 1

$10 x^{2} -11x+1=0\\\\ a=10;\ b=-11;\ c=1\\\\\\ \Delta=b^2-4ac\to \Delta=(-11)^2-4.10.1\to \Delta=121-40\to \boxed{\Delta=81}\\\\ x' \neq x''\\\\\\ x= \dfrac{-b\pm \sqrt{\Delta}}{2a} \to x= \dfrac{-(-11)\pm \sqrt{81}}{2.10} \to x= \dfrac{11\pm 9}{20} \to\\\\\\ x'= \dfrac{11+ 9}{20} \to x'= \dfrac{20}{20} \to \boxed{x'=1}\\\\\\ x''= \dfrac{11- 9}{20} \to x''= \dfrac{2}{20} \to \boxed{x''= \dfrac{1}{10} }\\\\ \\\\\boxed{\boxed{S=\{ \dfrac{1}{10}~;~1\}}}$

Answer 2

Resposta:

10×2-11×1=0

20-11×1=0

9×1=0

=9