Matemática, perguntado por anjaques, 1 ano atrás

1) -x²+2x+3=0
2)x²-6x+9=0
3)5x²-3x-2=0
4)4x²-5x-6=0
5)x²-7+10=0​

Soluções para a tarefa

Respondido por Aaron1
2

1)

Soma = -2/-1 = 2

Produto = -3

x' = 3

x'' = -1

2)

S = 6

P = 9

x' = 3

x" = 3

3)

Delta = (-3)^2-4.5.(-2)

delta = 9+40

delta = 49

-(-3)+-7/2.5

3+-7/10

x' = 1

x'' = -4/10 = -2/5

4)

delta = (-5)^2-4.4.(-6)

delta = 25 + 96

delta = 121

5+-11/8

x' = 2

x'' = -6/8 = -3/4

5)

S = 7

P = 10

X' = 2

X" = 5

Respondido por lau4814
1

1)-x²+2x+3=0

∆=b²-4ac

∆=(2)²-4(-1)(+3)

∆=4+12

∆=16

x=-b+√∆\2a

x=-(+2)+√16/-2

X=-2+- 4/-2

x'=-2+4/-2=+2/-2=-1

x"= -2-4/-2=-6/-2=3

s=(--1,3)

2)x²-6x+9=0

∆=(-6)²-4.1.9

∆=36-36

∆=0

x= -b+- √∆|2.a

x=-(-6)+-√∆\2

x=6+-0/2

x'=6+0/2=6/2=3

x"=6-0/2=6/2=3

s(3,3)

3)5x²-3x-2=0

∆=(-3)² -4.5.(-2)

∆=9+40

∆=49

x= -(-3)+-√49/2.5

x=3+-7/10

x'=3+7/10=10/10=1

x"=3-7/10=-4/10=-0,4

s(-0,4, 1)

4)4x²-5x-6=0

∆=(-5)²-4.4.(-6)

∆=25+96

∆=121

x=-(-5)+-√121/2.4

x=5+-11/8

x'=5+11/8=16/8=2

x"=5-11/8= -6/8=-0,75

5)x²-7+10=0

∆=(-7)²-4.1.10

∆=49-40

∆=9

x=-(-7)+-√9/2.1

x=7+-3/2

x'=7+3/2=10/2=5

x"=7-3/2=4/2=2

s=(2,5)

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