Question

1)(x+y+z)³,x=3,y=7 e z=2
pfvr me ajudem pra hj pfvrr

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Answer 1

Explicação passo a passo:

1)

(x+y+z)³

(3+7+2)³

12³ = 12.12.12 = 1728

4)

(2+8+6).2²

16.4 = 64

5)

(7-4).(7²-4²)

3.(49-16)

3.33 = 99

6)

6/2 + 12/3 + 20/5

3+4+4 = 11

7)

n²-n

10²-10

100-10 = 90

8)

5² + 1,5² + 0,75²

25 + 2,25 + 0,5625 = 27,8125

9)

2.3^4 + 3.3³ - 2.3²

2.81 + 3.27 - 2.9

162 + 81 - 18 = 225

10)

(4,5 + 3,5).(4,5-3,5)

8.1 = 8

11)

$\sqrt{8+4-2}$

8² + 4² - 2²

64 + 16 - 4 = 76