Question

1
_(x elevado a 2)+4-3x=0
2

Answer 1

Olá,

$\frac{1}{2} x {}^{2} + 4 - 3x = 0$

x²+8-6x=0

x²-6x+8=0

$x = \frac{ - ( - 6) + - \sqrt{( - 6) {}^{2} - 4 \times 1 \times 8 } }{2 \times 1}$

$x = \frac{6 + - \sqrt{36 - 32} }{2}$

$x = \frac{6 + - \sqrt{4} }{2}$

$x = \frac{6 + - 2}{2}$

$x = \frac{6 + 2}{ 2} \\ x = \frac{6 - 2}{2}$

$x = 4 \\ x = 2$


Espero ter te ajudado!