Question

1- Utilizando o que aprende sobre produtos notáveis, calcule: a) (a – 3)2 = b) (x + 5)2 = c) (2y – 1)2 = d) (r + 4) . (r - 4) = e) (2x + 3) . (2x – 3) = f) (y + 6) . (y - 6) =

Answer 1

Explicação passo-a-passo:

a)

(a - 3)² = a² - 2.a.3 + 3²

(a - 3)² = a² - 6a + 9

b)

(x + 5)² = x² + 2.x.5 + 5²

(x + 5)² = x² + 10x + 25

c)

(2y - 1)² = (2y)² - 2.2y.1 + 1²

(2y - 1)² = 4y² - 4y + 1

d)

(r + 4).(r - 4) = r² - 4²

(r + 4).(r - 4) = r² - 16

e)

(2x + 3).(2x - 3) = (2x)² - 3²

(2x + 3).(2x - 3) = 4x² - 9

f)

(y + 6).(y - 6) = y² - 6²

(y + 6).(y - 6) = y² - 36

Answer 2

Oie, Td Bom?!

a)

$= (a - 3) {}^{2}$

$= a {}^{2} - 2a \: . \: 3 + 3 {}^{2}$

$= a {}^{2} - 6a + 9$

b)

$= (x + 5) {}^{2}$

$= x {}^{2} + 2x \: . \: 5 + 5 {}^{2}$

$= x {}^{2} + 10x + 25$

c)

$= (2y - 1) {}^{2}$

$= (2y) {}^{2} - 2 \: . \: 2y \: . \: 1 + 1 {}^{2}$

$= 4y{}^{2} - 4y + 1$

d)

$= (r + 4) \: . \: (r - 4)$

$= r {}^{2} - 4 {}^{2}$

$= r {}^{2} - 16$

e)

$= (2x + 3) \: . \: (2x - 3)$

$= (2x) {}^{2} - 3 {}^{2}$

$= 4x {}^{2} - 9$

f)

$= (y + 6) \: . \: (y - 6)$

$= y {}^{2} - 6 {}^{2}$

$= y {}^{2} - 36$

Att. Makaveli1996