Question

1- Uma abelha se desloca 3600m a cada 360s, qual sua velocidade em m/s e km/h?
OBS: Utilizar uma casa após a vírgula. Favor constar o cálculo.

Answer 1

Resposta:

s = 3600 m = 3.6 km

s0 = 0 m = 0 km

t = 360 s = 360/3600 h = 0.1 h

t0 = 0 s = 0 h

v = ∆s / ∆t

v = (s - s0) / (t - t0)

v = (3600 - 0) / (360 - 0)

v = 3600 / 360

v = 10 m/s

v = ∆s / ∆t

v = (s - s0) / (t - t0)

v = (3.6 - 0) / (0.1 - 0)

v = 3.6 / 0.1

v = 36 km/h

Answer 2

$\Large\boxed{\begin{array}{l}\underline{\rm D~\!\!efinic_{\!\!,}\tilde ao~de~velocidade~m\acute edia}\\\\\sf V_m=\dfrac{\Delta~\!s}{\Delta~\!t}\\\underline{\rm convers\tilde ao~entre~velocidades}\\\sf m/s\longrightarrow^{\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\times3,6}~~km/h\\\sf km/h\longrightarrow^{\!\!\!\!\!\!\!\!\!\!\!\!\!\!\div3,6}~~~m/s\end{array}}$

$\Large\boxed{\begin{array}{l}\tt dados\begin{cases}\sf\Delta~\!s=3600~m\\\sf\Delta~\!t=360~s\\\sf V_m=?\end{cases}\\\underline{\rm soluc_{\!\!,}\tilde ao\!:}\\\sf V_m=\dfrac{\Delta~\!s}{\Delta~\!t}\\\\\sf V_m=\dfrac{3600}{360}\\\\\sf V_m=10~m/s\\\sf V_m(km/h)=10\times3,6=36~km/h\end{array}}$