Question

1)
$x = - b + \sqrt{ { \\ b}^{2} } - 4ac \: { }^{}$
calcule o valor de x para a=1, b=5 e c=6




2) a da foto.





(gente pfvr respondam)​

Answer 1

Resposta:

Explicação passo a passo:

$1)\\-5 + \sqrt{5^{2} } - 4 . 1 . 6\\\\-5 + \sqrt{25-24} \\\\-5 + \sqrt{1} \\\\-5 + 1 = x\\\\x=-4$

2)

$d=\frac{n(n-3)}{2} / n=10\\\\d=\frac{10.(10-3)}{2} \\\\d=\frac{10.7}{2}\\ \\d=\frac{70}{2} \\\\d=35$