Question

(1 sobre raiz de n) - (1 sobre raiz de n+1)=

Answer 1

$[tex] \frac{1}{ \sqrt{n} }* \frac{ \sqrt{n} }{ \sqrt{n} } - \frac{1}{ \sqrt{n+1} }* \frac{ \sqrt{n-1} }{ \sqrt{n-1} } \\ \\ \frac{ \sqrt{n} }{n} * \frac{ \sqrt{n-1} }{n-1} = \frac{(n-1) \sqrt{n}-n \sqrt{n-1}}{ n^{2}-n }$ =[/tex]