Question

1 sobre raiz de 3 menos 1

Answer 1

Racionalizando o denominador:

$\frac{1}{\sqrt3-1}*\frac{\sqrt3+1}{\sqrt3+1}=\frac{\sqrt3+1}{2}$

Answer 2

$\dfrac{1}{\sqrt{3}-1}$

Multiplique por $\dfrac{\sqrt{3}+1}{\sqrt{3}+1}$:

$\dfrac{1}{\sqrt{3}-1}\cdot\dfrac{\sqrt{3}+1}{\sqrt{3}+1}=\dfrac{1(\sqrt{3}+1)}{(\sqrt{3}-1)(\sqrt{3}+1)}=\dfrac{\sqrt{3}+1}{3-1}=\dfrac{\sqrt{3}+1}{2}$