Matemática, perguntado por gabrielasilva9147, 2 meses atrás

1)Sendo U=Q,vamos resolver as seguintes equações do 1° grau com uma incógnita.
A) 7 x + 1 - 5x = 9
B) Y + 9 y + 5 = - 15
C) 17 X - 1 = 15 + 3
D) 16 - x = x + 26
E)2.(y-2)+5.(2-y)=3.(2y+2)
F)5.( m + 1)- 3.(2m+1)-4.(5-m)

Soluções para a tarefa

Respondido por oi1331
0

Não fiz a F porque não tem igualdade, se preferir em forma de texto ai está:

a)7x + 1 - 5x = 9

7x -5x = 9 - 1

2x = 8

x = 8/2

x = 4

b)

y + 9y + 5 = -15

10y + 5 = -15

10y = -15 + 5

10y = -10

y = -10/10

y = -1

c)

17x - 1 = 15 + 3

17x - 1 = 18

17x = 18 + 1

17x = 19

x = 19/17

d)

16 - x = x + 26

-x -x = 26 - 16

-2x = 10

x = 10/-2

x = -5

e)

2.(y-2)=5.(2-y) = 3.(2y+2)

2.(y-2)+5.(2-y) = 3.(2y+2)

2y-4+10-5y=6y+6

2y+6-5y=6y+6

2y-5y-6y=-6+6

-9y=0

y = 0

Anexos:
Respondido por simonesantosaraujo91
0

Resposta:

A)2x=4

B)y=-2

C)x=19/17

D)x=-5

E)y=0

F)3m-18

Explicação passo-a-passo:

A)7x+1-5x=9

7x+1-5x=9

7x-5x

(7-5)x

2x

7x+1-5x=9

2x+1=9

2x+1-1=9-1

2x=9-1

2x+1=9

2x=9-1

2x=8

2x÷2=8÷2

x=8÷2

2x÷2=8÷2

x=4

2x=8

2x=4

Resposta

2x=4

B)y+9y+5=-15

y+9y+5=-15

y+9y

1y+9y

(1+9)y

10y

y+9y+5=-15

10y+5=-15

10y+5-5=-15-5

10y=-15-5

10y+5=-15

10y=-15-5

-15=-5

-(15+5)

-20

10y=-15-5

10y=-20

10y÷10=-20÷10

y=-20÷20

10y÷10=-20÷10

y=-2

10y=-20

y=-2

Resposta

y=-2

C)17x-1=15+3

17x-1=15+3

17x-1=18

17x-1+1=18+1

17x=18+1

17x-1=18

17x=18+1

17x=19

17x÷17=19÷17

x=19÷17

17x÷17=19÷17

x=19/17

17x=19

x=19/17

Resposta

x=19/17

D)16-x=x+26

16-x=x+26

16-x-x=x+26-x

16-x-x=26

16-x=x+26

16-x-x=26

16-x=x+26

16-x-x-16=26-16

-x-x=26-16

16-x=x+26

-x-x=26-16

-x-x

-1x-x

-x-x

1x-1x

(-1-1)x

-2x

-x-x=26+16

-2x=26-16

-x-x=26+16

-2x=10

-2x÷(-2)=10÷(-2)

x=10÷(-2)

-2x÷(-2)=10÷(-2)

x=-10÷2

-2x÷(-2)=10÷(-2)

x=-5

-2x=10

x=-5

Resposta

x=-5

E)2(y-2)+5(2-y)=3(2y+2)

2(y-2)+5(2-y)=3(2y+2)

2(y-2)

2y-2×2

2y-4

2(y-2)+5(2-y)=3(2y+2)

2y-4+5(2-y)=3(2y+2)

2(y-2)+5(2-y)=3(2y+2)

5(2-y)

5×2-5y

10-5y

2(y-2)+5(2-y)=3(2y+2)

2y-4+10-5y=3(2y+2)

2(x-2)+5(2-y)=3(2y+2)

3(2y+2)

3×2y+3×2

6y+3×2

3×2y+3×2

6y+6

2(y-2)+5(2-y)=3(2y+2)

2y-4+10-5y=6y+6

2y-5y

(2-5)y

-3y

2y-4+10-5y=6y+6

-3y-4+10=6y+6

2y-4+10-5y=6y+6

-4+10

+(10-4)

6

2y+4+10-5y=6y+6

-3y+6=6y+6

-3y=6y

-3y-6y=6y-6y

-3y-6y=0

-3y=6y

-3y-6y=0

-3y-6y

(-3-6)y

-9y

-3y-6y=0

-9y=0

-9y÷(-9)=0÷(-9)

y=0÷(-9)

-9y÷(-9)=0÷(-9)

y=0

-9y=0

y=0

Resposta

y=0

F)5(m+1)-3(2m+1)-4(5-m)

5(m+1)-3(2m+1)-4(5-m)

5m+5-3(2m+1)-4(5-m)

5(m+1)-3(2m+1)-4(5-m)

-3(2m+1)

-3×2m-3

-6m-3

5(m+1)-3(2m+1)-4(5-m)

5m+5-6m-3-4(5-m)

5(m+1)-3(2m+1)-4(5-m)

-4(5-m)

-4×5-4×(-m)

-20-4×(-m)

-4×5-4×(-m)

-20+4m

5(m+1)-3(2m+1)-4(5-m)

5m+5-6m-3-20+4m

5m-6m+4m

(5-6+4)m

3m

5m+5-6m-3-20+4m

3m+5-3-20

5m+5-6m-3-20+4m

5-3-20

5-23

-18

5m+5-6m-3-20+4m

3m-18

Resposta

3m-18

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