Question

(1) Sendo log 2 = 0,301, log 3 = 0,477 calcule:
a) log 24=
b) log 15=

(2) dados log 2 = A e log 3 = B, determine:
a) log 48=
b) log 30=

Answer 1

(1)
$a) \ log24=log(3*2^3)=log3+3log2=0,477+3*(0,301)=1,38\\ \\ b) \ log15=log(3*5)log3+log5=log3+log(\frac{10}{2})=\\ =log3+log10-log2=0,477+1-0,301=1,176$

(2)

$a) \ log48=log(2^4*3)=4log2+log3=4A+B\\ \\ b) \ log30=log(3*10)=log3+log10=B+1$