Question

1) Sendo f(x)= x2– x -12, determine:

Answer 1

Resposta:

1)a) a= 1

b= -1

c= -12

b) f(2)= 2²-2-12= 4 - 14 = - 10

c) f(-2) = 4 + 2 -12= - 6

d) f(0) = -12

e) f(4)= 16 - 4 - 12 = 0

2) ∆=b² - 4ac

∆ = 1 - 4 . 1 . -12

∆ = 1 + 48

∆ = 49

3) √ 49 = +-7

4) x= - b + √∆/ 2a

x= 1 + √ 49/2 . 1

x= (1 + 7) /2

x= 8/2= 4

5) x= 1 - √49/2

x= (1 - 7) /2 =. -6/2 = - 3