Question

1 sendo f (x)= x2 - 5x + 6, determine

a) os valores de x de modo que f (x) seja 0

b)os valores de x de modo que f (x) seja 20

Answer 1

a) 0= x²-5x+6
5±√5²-4.1.6/2
$\frac{5+ \sqrt{1} }{2}$
$\frac{5+1}{2} = 3$$\frac{5-1}{2}= 2$
S={2,3}
b)20=x²-5x+6
0=x²-5x-14
5²±√5²-4.1.-14/2
25±√81/2
$\frac{25+9}{2} = 17 \frac{25-9}{2}=8$
S= {8,17}

Answer 2

a) 5±√5²-4.1.6/2

S={2,3}

b)20=x²-5x+6

0=x²-5x-14

5²±√5²-4.1.-14/2

25±√81/2

S= {8,17}