Question

1)Sendo f ( x ) = 3 x + 7 calcule:

a) f(0)=

b) f ( 1 ) =

c) f ( 2 ) =

d) f ( - 2 ) =

e) f ( - 1 ) =

f) f ( 5 ) =

2) Sendo f ( x ) = 1 - 2x calcule

a) f ( 5 ) =

b) f ( 0 ) =

c) f ( - 5 ) =

d) f ( 1 ) =

e) f ( - 2 ) =

3) Dada a função f (x ) = - 3 x - 9 calcule

a) f (- 1 ) =

b) f ( 0 ) =

c) f ( 3 ) =

d) f ( - 3 ) =

e )f ( ⅓ ) =

​

Answer 1

Explicação passo-a-passo:

1)Sendo f ( x ) = 3 x + 7 calcule:

a)

f(0)=3.(0)+7

f(0)=0+7

f(0)=7

b)

f(1)=3.(1)+7

f(1)= 3+7

f(1)=10

c)

f(2) =3.(2)+7

f(2)=6+6

f(2)=13

d)

f ( - 2 ) =3.(-2)+7

f(-2)=-6+7

f(-2)=1

e)

f ( - 1 ) =3.(-1)+7

f(-1)=-3+7

f(-1)=4

f)

f ( 5 ) =3.(5)+7

f(5)=15+7

f(5)=22

2) Sendo f ( x ) = 1 - 2x calcule

a)

f ( 5 ) =1-2.(5)

f(5)=1-10

f(5)=-9

b)

f ( 0 ) =1-2.(0)

f(0)=1-0

f(0)=1

c)

f ( - 5 ) =1-2.(-5)

f(-5)=1+10

f(-5)=11

d)

f ( 1 ) =1-2.(1)

f(1)=1-2

f(1)=-1

e)

f ( - 2 ) =1-2.(-2)

f(-2)=1+4

f(-2)=5

3) Dada a função f (x ) = - 3 x - 9 calcule

a)

f (- 1 ) = -3.(-1)-9

f(-1)=3-9

f(-1)=-6

b)

f ( 0 ) =-3.(0)-9

f(0)=0-9

f(0)=-9

c)

f ( 3 ) =-3.(3)-9

f(3)=-9-9

f(3)=-18

d)

f ( - 3 ) =3.(-3)-9

f(-3)=-9-9

f(-3)=-18

e )

f ( ⅓ ) =-3.(1/3)-9

f(1/3)=-1-9

f(1/3)=-10