Question

1) Resolver as seguintes equações:

4x - 1 = 3.(x-1)

4.( x + 1) = 12

3.( x - 2) = 2x - 4

- 5.(x-4)= - 5

2.(x - 1) = 3x + 4

9.( x-3) + 1 = 18

3.(x-1)- 7 = 15

7.( x + 2) = 1​

Answer 1

Resposta:

4x - 1 = 3.(x-1)

$4x - 1 = 3x - 3 \\ 4x - 1 - 3x + 3 = 0 \\ x + 2 = 0 \\ x = - 2$

4.( x + 1) = 12

$4x + 4 = 12 \\ 4x = 12 - 4 \\ 4x = 8 \div (4) \\ x = 2$

3.( x - 2) = 2x - 4

$3x - 6 = 2x - 4 \\ 3x - 6 - 2x + 4 = 0 \\ x - 2 = 0 \\ x = 2$

- 5.(x-4)= - 5

$- 5x + 20 = - 5 \\ - 5x + 20 + 5 = 0 \\ - 5x +25 = 0 \\ - 5x = - 25 \div ( - 1) \\ 5x = 25 \div (5) \\ x = 5$

2.(x - 1) = 3x + 4

$2x - 2 = 3x + 4 \\ 2x - 2 - 3x - 4 = 0 \\ - x - 6 = 0 \\ - x = 6 \times ( - 1) \\ x = - 6$

9.( x-3) + 1 = 18

$9x - 27 + 1 = 18 \\ 9x - 26 = 18 \\ 9x - 26 - 18 = 0 \\ 9x - 44 = 0 \\ 9x = 44 \\ \\ x = \frac{44}{9}$

3.(x-1)- 7 = 15

$3x - 3 - 7 = 15 \\ 3x - 10 = 15 \\ 3x - 10 - 15 = 0 \\ 3x - 25 = 0 \\ 3x = 25 \\ \\ x = \frac{25}{3}$

7.( x + 2) = 1

$7x + 14 = 1 \\ 7x + 14 - 1 = 0 \\ 7x + 13 = 0 \\ \\ 7x = - 13 \\ \\ x = - \frac{13}{7}$