Matemática, perguntado por Fanyeste, 8 meses atrás

1) resolva os sistemas abaixo.
a)x+2y=15
X-2y=3

B)3x+y=14
4x-3y=3

C )2x+2y=10
3x-y=7

D)x+2y=9
x-2y=-3
Mim ajudem pfvr

Soluções para a tarefa

Respondido por JovemLendário
1

olá !!!

a)\\x+2y=15\\x-2y=3\\\\x=15\\x=3\\soma\\2x=18\\x=18/2\\x=9\\\\a)1)\\x+2y=15\\9+2y=15\\2y=15+9\\2y=24\\y=24/2\\y=12\\\\a)2)x-2y=3\\9-2y=3\\-2y=3-9\\-2y=-6\\2y=6\\y=6/2\\y=3\\\\\\

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b)\\3x+y=14\\4x-3y=3\\\\3x=14\\4x=3\\soma\\7x=17\\x=17/7\\x=2,4\\\\b)1)\\3x+y=14\\7,2+y=14\\y=14-7,2\\y=6,8\\\\b)2)\\4x-3y=3\\9,6-3y=3\\-3y=3-9,6\\-3y=-6,6\\3y=6,6\\y=6,6/3\\y=2,2\\\\

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c)\\2x+2y=10\\3x-y=7\\\\2x=10\\3x=7\\soma\\5x=17\\x=17/5\\x=3.4\\\\c)1)\\2x+2y=10\\6,8+2y=10\\2y=10-6,8\\2y=3,2\\y=3,2/2\\y=1,6\\\\c)2)\\3x-y=7\\10,2-y=7\\-y=7-10,3\\y=3,3\\\\

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d)\\x+2y=9\\x-2y=-3\\\\x=9\\x=-3\\soma\\2x=6\\x=6/2\\x=3\\\\d)1)\\x+2y=9\\3+2y=9\\2y=9-3\\2y=6\\y=6/2\\y=3\\\\d)2)\\x-2y=-3\\3-2y=-3\\-2y=-3-3\\2y=6\\y=6/2\\y=3

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espero ter ajudado

att: jovem lendário

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