Question

1) Resolva as questões (sem usar Bhaskara)

a)
${x}^{2} - 3 = 0$
b)
$6 {x}^{2} = 5x$
c)
${( \times + 2)}^{2} = 4$

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Answer 1

Resposta:

a )

${x}^{2 } - 3 = 0$

${x}^{2} = 3$

$x = \sqrt{3}$

$x = ± \sqrt{3}$

b )

6x² = 5x

6x² - 5x = 0

x = 0

c )

( x + 2 )² = 4

x² + 4x + 4 - 4 = 0

x² + 4x = 0

x1 = 0

x2 = -4

Espero ter ajudado.