1.Resolva as expressões numéricas:
a)70-[12+(5x2-1)+6]=
b)8:2+[15-(4x2+1)]=
c)9+[4+2x(6-4)+(2+5)]-8=
d)50+{10-2x[(6+4:2)-(10-3)]=
Soluções para a tarefa
Respondido por
1
a-43
b-10
c-16
d-********nao sei ****
b-10
c-16
d-********nao sei ****
Respondido por
2
a) 70-[12+(5*2-1)+6]
= 70-[12+(10-1)+6]
= 70-[12+9+6]
= 70-[12+15]
= 70-27
= 43
b) 8:2+[15-(4*2+1)]
= 8:2+[15-(8+1)]
= 8:2+[15-9]
= 8:2+6
= 4+6
= 10
c) 9+[4+2*(6-4)+(2+5)]-8
= 9+[4+2*2+7]-8
= 9+[4+4+7]-8
= 9+15-8
= 16
d)50+{10-2*[(6+4:2)-(10-3)]}
= 50+{10-2*[(6+2)-7]}
= 50+{10-2*[8-7]}
= 50+{10-2*[8-7]}
= 50+{10-2*1}
= 50+{10-2}
= 50+8
=58
= 70-[12+(10-1)+6]
= 70-[12+9+6]
= 70-[12+15]
= 70-27
= 43
b) 8:2+[15-(4*2+1)]
= 8:2+[15-(8+1)]
= 8:2+[15-9]
= 8:2+6
= 4+6
= 10
c) 9+[4+2*(6-4)+(2+5)]-8
= 9+[4+2*2+7]-8
= 9+[4+4+7]-8
= 9+15-8
= 16
d)50+{10-2*[(6+4:2)-(10-3)]}
= 50+{10-2*[(6+2)-7]}
= 50+{10-2*[8-7]}
= 50+{10-2*[8-7]}
= 50+{10-2*1}
= 50+{10-2}
= 50+8
=58
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