1- Resolva as equeçoes, sendo u=Q:
A) 4(x+10)-2(x-5)=0
B) 3(2x-1)= -2 (x+3)
C) 15+3 (x+2)= -7+2(x+1)
D) -5(-x-4)= -5
E) 2x-3=7-2 (2x-13)
Soluções para a tarefa
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A) 4(x+10)-2(x-5)=0
4x +40 -2x +10 = 0
4x -2x = -40 -10
2x = - 50
2x = -50/2
x = - 25
B) 3(2x-1)= -2 (x+3)
6x -3 = -2x - 6
6x +2x = - 6 +3
8x = -3
x = - 3/8
C) 15+3 (x+2)= -7+2(x+1)
15 + 3x +6 = -7 +2x +2
3x -2x = -7 -15 -6 +2
x = -28 +2
x = - 26
D) -5(-x-4)= -5
+5x +20 = -5
5x = -5 -20
5x = -25
x = -25/5
x = - 5
E) 2x-3=7-2 (2x-13)
2x -3 = 7 -4x - 26
2x +4x = 7 +3 -26
6x = 10 -26
6x = -16
x = -16/6 simplificando -16 e 6 por 2
x = - 8/3
4x +40 -2x +10 = 0
4x -2x = -40 -10
2x = - 50
2x = -50/2
x = - 25
B) 3(2x-1)= -2 (x+3)
6x -3 = -2x - 6
6x +2x = - 6 +3
8x = -3
x = - 3/8
C) 15+3 (x+2)= -7+2(x+1)
15 + 3x +6 = -7 +2x +2
3x -2x = -7 -15 -6 +2
x = -28 +2
x = - 26
D) -5(-x-4)= -5
+5x +20 = -5
5x = -5 -20
5x = -25
x = -25/5
x = - 5
E) 2x-3=7-2 (2x-13)
2x -3 = 7 -4x - 26
2x +4x = 7 +3 -26
6x = 10 -26
6x = -16
x = -16/6 simplificando -16 e 6 por 2
x = - 8/3
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