Question

1) Resolva as equações, sendo​

Answer 1

$\texttt{Olhar para baixo}$

$\boxed{\begin{array}{ccc} {x}^{4} - 5 {x}^{2} + 4 = 0 \\ \\ {u}^{2} - 5u + 4 = 0 \\ \\ \Delta = \dfrac{ - ( - 5) \pm \sqrt{ - {5}^{2} - 4(4)} }{2} \\ \\ \Delta = \dfrac{5 \pm \sqrt{9} }{2} \\ \\ u= \dfrac{5 + 3}{2} \\ \\u= 4 \\ \\ u = \dfrac{5 - 3}{2} \\ \\ u = 1\end{array}}$

$\rule{10cm}{0.1mm}$

$x^2=4\\ \\ x=\pm\sqrt{4}\\ \\ x=\pm 2\\\\ x^2=1\\ \\ x=\pm\sqrt{1}\\ \\ x=\pm1\\ \\ \boxed{V=\{-2,-1,1,2\}}\checkmark$