Question

1) Resolva as equacoes matrizes

A)

[ 1 2 -1 ] =1
[ 0 1 x ]
[ 1 x -1 ]


B)

[2 3 -2]
[0 1 X] =2
[2 x -3]

Answer 1

A)


| 1 2 -1 | 1 2
| 0 1 X | 0 1 = 1
| 1 X -1 | 1 X


-1 + 2x - x² + 1 = 1
-x² + 2x - 1 = 0


∆ = 2² - 4.(-1).(-1)
∆ = 4 - 4
∆ = 0

x = -2 ± 0/2.(-1)

x = -2 ± 0/-2 = -2/-2 = 1


S={ 1 }
.
.
.
B)

| 2 3 -2 | 2 3
| 0 1 X | 0 1 = 2
| 2 X -3 | 2 X


-6 + 6x - 2x² + 4 = 2
-2x² + 6x -2 - 2 = 0
-2x² + 6x - 4 = 0


∆ = 6² - 4.(-2).(-4)
∆ = 36 - 32
∆ = 4


x = -6 ± √4/2.(-2)

x = -6 ± 2/-4

x = -6 - 2/-4 = -8/-4 = 2

x = -6 + 2/-4 = -4/-4 = 1


S={ 2, 1 }




★Espero ter ajudado! tmj