Question

1-resolva as equações
a) log 2 (x+1) =5
b) log 3(2x-2) =2
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Answer 1

a)

$log_{2}(x + 1) = 5 \\ x + 1 = {2}^{5} \\ x + 1 = 32 \\ x = 32 - 1 \\ x = 31$

b)

$log_{3}(2x - 2) = 2 \\ 2x - 2 = {3}^{2} \\ 2x - 2 = 9 \\ 2x = 9 + 2 \\ 2x = 11$

$x = \frac{11}{2}$

Answer 2

Resposta:

a) 2 (x+1) =5

2x+2 =5

2x= 5 -2

2x= 3

x= 3

2

x= 1,5

b) 3 (2x-2)= 2

6x-6= 2

6x= 2+6

6x= 8

x= 8

6

x= 1,3...