Matemática, perguntado por jhonkellyson, 1 ano atrás

1.resolva as equaçao

a) 3(2x-5)+5x=4(1-2x

c) 2094+3x)+5(3x+20)=9+10x

d) 509x-3)-20x=40(3+2x)+15x

e)9(3x+5)+12x-5=9(7

Soluções para a tarefa

Respondido por 3478elc
0


a) 3(2x-5)+5x=4(1-2x)
 
  6
x - 10 + 5x = 4 - 8x ==> 11x+8x = 4 + 10 ==> 19x = 14 ==> x = 14/19
========================================================
c) 20(4+3x)+5(3x+20)=9+10x

80+60x+15x+100= 9+10x ==> 80+75x-10x= 9 - 180

65x = - 171 ==> x = - 171/65
=============================================
d) 50(x-3)-20x=40(3+2x)+15x

50x-150-20x=120+80x+15x ==> 30x-150= 95x + 120

95x- 30x = - 150 - 120 ==> 65x = - 270 ==> x = -270/65
===================================================
e)9(3x+5)+12x-5=9(7)

27x+45+12x-5=63

39x = 63-40

39x = 23

x = 23/39
Perguntas interessantes