Question

1)Resolva:

A)(5x²y+3xy²) + (x2y+2xy²)

B)(7y²-12y+15) - (4x²+16y-18)

Answer 1

$A)\\ \\ (5x^{2} y+3xy^{2} )+(x^{2}y+2xy^{2})=\\ \\5x^{2} y+x^{2}y+3xy^{2}+2xy^{2} =\\ \\ 6x^{2} y+5xy^{2} =xy(6x+5y)$

$B)\\ \\ (7y^{2} -12y+15)-(4x^{2} +16y-18)=\\ \\ 7y^{2} -12y+15-4x^{2} -16y+18\\ \\ agrupe~os~termos~semelhantes~e~efetue:\\ \\ 7y^{2} -12y-16y+4x^{2} +15+18=\\ \\ 7y^{2} -28y+4x^{2} +33=\\ \\ 7y(y-4)+4x^{2} +33$

Answer 2

$A)\\ \\ (5x^{2} y+3xy^{2} )+(x^{2}y+2xy^{2})=\\ \\ 5x^{2} y+x^{2}y+3xy^{2}+2xy^{2} =\\ \\ 6x^{2} y+5xy^{2} =xy(6x+5y)$

$B)\\ \\ (7y^{2} -12y+15)-(4x^{2} +16y-18)=\\ \\ 7y^{2} -12y+15-4x^{2} -16y+18\\ \\ agrupe~os~termos~semelhantes~e~efetue:\\ \\ 7y^{2} -12y-16y+4x^{2} +15+18=\\ \\ 7y^{2} -28y+4x^{2} +33=\\ \\ 7y(y-4)+4x^{2} +33$