Question

1 - Resolva:
( -1)³
(5)

(-1)⁴
(2)

(-6)⁰
(5)

(+15)²
(9)

(+3)³
(7)

2 - Qual é o valor do expoente x?
2ˣ = 1
10ˣ = 1

Answer 1

Explicação passo-a-passo:

1)

a)

$\sf \left(-\dfrac{1}{5}\right)^3=\left(-\dfrac{1}{5}\right)\cdot\left(-\dfrac{1}{5}\right)\cdot\left(-\dfrac{1}{5}\right)$

$\sf \left(-\dfrac{1}{5}\right)^3=-\dfrac{1}{125}$

b)

$\sf \left(-\dfrac{1}{2}\right)^4=\left(-\dfrac{1}{2}\right)\cdot\left(-\dfrac{1}{2}\right)\cdot\left(-\dfrac{1}{2}\right)\cdot\left(-\dfrac{1}{2}\right)$

$\sf \left(-\dfrac{1}{2}\right)^4=\dfrac{1}{16}$

c)

$\sf \left(-\dfrac{6}{5}\right)^0=1$

d)

$\sf \left(+\dfrac{15}{9}\right)^2=\left(+\dfrac{15}{9}\right)\cdot\left(+\dfrac{15}{9}\right)$

$\sf \left(+\dfrac{15}{9}\right)^2=\dfrac{225}{81}$

e)

$\sf \left(+\dfrac{3}{7}\right)^3=\left(+\dfrac{3}{7}\right)\cdot\left(+\dfrac{3}{7}\right)\cdot\left(+\dfrac{3}{7}\right)$

$\sf \left(+\dfrac{3}{7}\right)^3=\dfrac{27}{343}$

2)

a)

$\sf 2^x=1$

$\sf 2^x=2^0$

Igualando os expoentes:

$\sf x=0$

b)

$\sf 10^x=1$

$\sf 10^x=10^0$

Igualando os expoentes:

$\sf x=0$