Question

1) racionalize os dominadores
a) 3 sobre raiz de 10
b) 1 sobre raiz de 5
c) 4 sobre raiz de 6
d) 2 sobre raiz de 8

Answer 1

Explicação passo-a-passo:

$a)\\ {3\over\sqrt{10} }={3\sqrt{10} \over\sqrt{10} .\sqrt{10} }={3\sqrt{10} \over\sqrt{100} }={3\sqrt{10} \over10}\\ \\ b)\\ {1\over\sqrt{5} }={\sqrt{5} \over\sqrt{5} .\sqrt{5} }={\sqrt{5} \over\sqrt{25} }={\sqrt{5} \over5}$

$c)\\{4\over\sqrt{6} }={4\sqrt{6} \over\sqrt{6} .\sqrt{6} }={4\sqrt{6} \over\sqrt{36}}={\not4^2\sqrt{6} \over\not6_3}={2\sqrt{6} \over3}\\ \\ d)\\ {2\over\sqrt{8} }={2\over\sqrt{2^2.2} }={\not2\over\not2\sqrt{2} }={1\over\sqrt{2} }={\sqrt{2} \over\sqrt{2} .\sqrt{2} }={\sqrt{2} \over\sqrt{4} }={\sqrt{2} \over2}$