1- Qual a solução dos sistemas a seguir?
a+2b = 2 a+b : 2 = 2
3a+b=20 a-b : 4 = 4
Soluções para a tarefa
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1°
{a+2b=2
{(a+b)÷2=2
a=2-2b
(a+b)÷2=2
(2-2b+b)÷2=2
(2-b)÷2=2
2-b=2×2
2-b=4
-b=4÷2
-b=2
b=-2
a=2-2b
a=2-2×(-2)
a=2+4
a=6
a=6, b=-2
2°
{3a+b=20
{(a-b)÷4=4
b=20-3a
(a-20-3a)÷4=4
(-2a-20)÷4=4
-2a-20=4×4
-2a-20=16
-2a=16+20
-2a=36
a=36÷(-2)
a=-18
b=20-3a
b=20-3×(-18)
b=20+54
b=74
a=-18, b=74
{a+2b=2
{(a+b)÷2=2
a=2-2b
(a+b)÷2=2
(2-2b+b)÷2=2
(2-b)÷2=2
2-b=2×2
2-b=4
-b=4÷2
-b=2
b=-2
a=2-2b
a=2-2×(-2)
a=2+4
a=6
a=6, b=-2
2°
{3a+b=20
{(a-b)÷4=4
b=20-3a
(a-20-3a)÷4=4
(-2a-20)÷4=4
-2a-20=4×4
-2a-20=16
-2a=16+20
-2a=36
a=36÷(-2)
a=-18
b=20-3a
b=20-3×(-18)
b=20+54
b=74
a=-18, b=74
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