Question

1) Os catetos de um triângulo retângulo medem 4 cm e 2 cm. Calcule a medida de sua hipotenusa. ​

Answer 1

$\large\boxed{\begin{array}{l}\rm x^2=2^2+4^2\\\rm x^2=4+16\\\rm x^2=20\\\rm x=\sqrt{20}\\\rm x=\sqrt{4\cdot5}\\\rm x=2\sqrt{5}\end{array}}$

Answer 2

$\large\boxed{\begin{array}{lr}x {}^{2} = 4 {}^{2} + 2 {}^{2} \\ x {}^{2} = 16 + 4 \\ x {}^{2} = 20 \\ x = \sqrt{20} \\ x = \sqrt{4.5} \\ x = \red{2 \sqrt{5}} \end{array}}$