Question

1- Obtenha a equação de conversão entre as escalas Fahrenheit e Kelvin.

Answer 1

$\frac{EBULICAO-FUSAO}{TK-FUSAO} = \frac{EBULICAO-FUSAO}{TF-FUSAO} \\ \\ \frac{373-273}{TK-273} = \frac{212-32}{TF-32} \\ \\ \frac{100}{TK-273} = \frac{180}{TF-32} : 20 \\ \\ \frac{5}{TK-273} = \frac{9}{TF-32}$