Matemática, perguntado por cauagustavorodrigues, 3 meses atrás

1. M.d.c

(A) m.d.c (1.860)

(B) m.d.c (24,48)

(C) m.d.c (36,24)

(D) m.d.c (30,15)

(E) m.d.c (12,36)

(F) m.d.c (80,25) me ajudem por favor


Math739: não entendi o da letra A tá certo?
cauagustavorodrigues: Ah desculpa é 18, 60
Math739: ok
cauagustavorodrigues: Te dei coração lá no teu perfil :) ❤
cauagustavorodrigues: Me ajuda por favor
cauagustavorodrigues: Oi mano

Soluções para a tarefa

Respondido por Math739
3

\Large\boxed{\begin{array}{l} \rm m\cdot d\cdot c\,(18,60)=6\\\\\begin{array}{r|l}18,60&2\\9,30&3\\3,10&\overline{2\cdot3=6}\end{array}\end{array}}

\Large\boxed{\begin{array}{l}\rm m\cdot d\cdot c\,(24,48)=24\\\\ \begin{array}{r|l}24,48&2\\12,24&2\\6,12&2\\3,6&3\\1,2&\overline{2^3\cdot3=24}\end{array}\end{array}}

\Large\boxed{\begin{array}{l} \rm m\cdot d\cdot c\,(36,24)=12\\\\\begin{array}{r|l}36,24&2\\18,12&2\\9,6&3\\3,2&\overline{2^2\cdot3=12}\end{array}\end{array}}

\Large\boxed{\begin{array}{l} \rm m\cdot d\cdot c\,(30,15)=15\\\\\begin{array}{r|l}30,15&3\\10,5&5\\2,1&\overline{3\cdot5=15}\end{array}\end{array}}

\Large\boxed{\begin{array}{l} \rm m\cdot d\cdot c\,(12,36)=12\\\\\begin{array}{r|l}12,36&2\\6,18&2\\3,9&3\\1,3&\overline{2^2\cdot3=12}\end{array}\end{array}}

\Large\boxed{\begin{array}{l} \rm m\cdot d\cdot c\,(80,25)=5\\\\\begin{array}{r|l}80,25&5\\16,5\end{array}\end{array}}


cauagustavorodrigues: Obrigado manooo ❤
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