Question

1) F(x) = 3x² -6x+1
2) F(x) = -x² + x -2
3) F (x) = -3x² + 2x - 4
4) F (x) = x² + 1
5) F (x) = 4x² - 10x + 4
6) F (x) = x² + 3x - 10
7) F (x) = x² - 6x + 12​

Answer 1

Resposta:

$f(x)=3x^2-6x+1\\3x^2-6x+1=0\\\Delta=36-12=24\\x'=\frac{6-2\sqrt{6}}{6}=\frac{3-\sqrt{6} }{3}\\x''=\frac{3+\sqrt{6}}{3} \\\\f(x)=-x^2+x-2\\-x^2+x-2=0\\\Delta=1-8=-7\\S=\{\}\\\\f(x)=-3x^2+2x-4\\-3x^2+2x-4=0\\\Delta=4-48=-44\\S=\{\}\\\\f(x)=x^2+1\\x^2+1=0\\\Delta=-4\\S=\{\}\\\\f(x)=4x^2-10x+4\\4x^2-10x+4=0\\\Delta=100-64=36\\x'=\frac{10-6}{8}=\frac{1}{2}\\x''=\frac{10+6}{8}=2\\\\f(x)=x^2+3x-10\\x^2+3x-10=0\\\Delta=9+40=49\\x'=\frac{-3-7}{1}=-10\\x''=-3+7=4$

$\\\\f(x)=x^2-6x+12\\x^2-6x+12=0\\\Delta=36-48=-12\\S=\{\}$