Question

1-Escreva no caderno os resultados das divisões abaixo

a)(x³y+x²y²+x²y)÷(x²y)

b)(6x⁴y²-6x³y²+6x²y²)÷(6x²y²)

c)(3a³b³-3a²b⁴+3a²b³)÷(3a²b³)​

Answer 1

Resposta:

Explicação passo a passo:

a)(x³y+x²y²+x²y)÷(x²y) =

X + y + 1

b)(6x⁴y²-6x³y²+6x²y²)÷(6x²y²)

X² - x + 1

c)(3a³b³-3a²b⁴+3a²b³)÷(3a²b³)​

a - b + 1

Answer 2

Explicação passo-a-passo:

$\frac{x {}^{3} y}{x {}^{2}y } + \frac{x {}^{2} y {}^{2} }{x {}^{2} y} + \frac{x {}^{2}y }{x {}^{2}y } = x {}^{3 - 2} y {}^{1 - 1} + x {}^{2 - 2} y {}^{2 - 1} + 1 =$

$x + y + 1$

$b)(6x {}^{4} y {}^{2} - 6x {}^{3} y {}^{2} + 6x {}^{2} y {}^{2} ) \div (6x {}^{2} y {}^{2} ) =$

$\frac{6x {}^{4} y {}^{2} }{6x {}^{2}y {}^{2} } - \frac{6x {}^{3}y {}^{2} }{6x {}^{2} y {}^{2} } + \frac{6x {}^{2} y {}^{2} }{6x {}^{2} y {}^{2} } =$

$x {}^{4 - 2} - x {}^{3 - 2} + 1 = x {}^{2} - x + 1$

$c)(3a {}^{3} b {}^{3} - 3a {}^{2} b {}^{4} + 3a {}^{2} b {}^{3} ) \div (3a {}^{2} b {}^{3} ) =$

$\frac{3a {}^{3}b {}^{3} }{3a {}^{2} b {}^{3} } - \frac{3a {}^{2} b {}^{4} }{3a {}^{2}b {}^{3} } + \frac{3a {}^{2}b {}^{3} }{3a {}^{2}b {}^{3} } = a {}^{3 - 2} - b {}^{4 - 3} + 1 = a - b + 1$