Question

1) Escreva a equação na forma reduzida (Foto da equação abaixo)

Answer 1

$\frac{2}{x}-\frac{1}{2} =\frac{x}{x-4} \\ \\\frac{x-4}{-2x}=\frac{x}{x-4}\\x^2-8x+16=-2x^2\\\\\\\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{3x^2-8x+16=0}}}}}}}}}}}}}}}}$

Answer 2

Oie, Td Bom?!

$\frac{2}{x} - \frac{1}{2} = \frac{x}{x - 4}$

$\frac{2}{x} - \frac{1}{2} - \frac{x}{x - 4} = 0$

$\frac{2(x - 4) \: . \: 2}{2(x - 4)x} - \frac{x \: . \: (x - 4) \: . \: 1}{x \: . \: (x - 4) \: . \: 2} - \frac{2x \: . \: x}{2x \: . \: (x - 4)} = 0$

$\frac{4(x - 4)}{2x \: . \: (x - 4)} - \frac{x \: . \: (x - 4)}{2x \: . \: (x - 4)} - \frac{2x {}^{2} }{2x \: . \: (x - 4)} = 0$

$\frac{4(x - 4) - x \: . \: (x - 4) - 2x {}^{2} }{2x \: . \: (x - 4)} = 0$

$\frac{4x - 16 - x {}^{2} + 4x - 2x {}^{2} }{2x \: . \: (x - 4)} = 0$

$\frac{8x - 16 - 3x {}^{2} }{2x \: . \: (x - 4)} = 0$

$8x - 16 - 3x {}^{2} = 0$

$- 3x {}^{2} + 8x - 16 = 0 \: . \: ( - 1)$

$3x {}^{2} - 8x + 16 = 0$

Att. Makaveli1996