Question

1. Encontre o quadrado de cada um dos seguintes binômios.
a) [x+5]^2
b) [a+3]^2
c) [4+m]^2
d) [x+a]^2
e) [3x+2]^2
f) [4a+1]^2
g) [2x+y^2]^2
h)[1/2x+4a]^2
me ajudem pfv

Answer 1

Lembrando que:

$(a + b) {}^{2} = {a}^{2} + 2ab + {b}^{2}$

Logo:

a)

$(x + 5 {)}^{2} = {x}^{2} + 10x + 25$

b)

$(a + 3 {)}^{2} = {a}^{2} + 6a + 9$

c)

$(4 + m {)}^{2} = 16 + 8m + {m}^{2}$

d)

$(x + a {)}^{2} = {x}^{2} + 2xa + {a}^{2}$

e)

$(3x + 2 {)}^{2} = 9 {x}^{2} + 12x + 4$

f)

$(4a + 1 {)}^{2} = 16 {a}^{2} + 8a + 1$

g)

$(2x + {y}^{2} {)}^{2} = 4 {x}^{2} + 4x {y}^{2} + {y}^{4}$

h)

$( \frac{1}{2} x + 4a {)}^{2} = \frac{1}{4} {x}^{2} + 4ax + 16 {a}^{2}$

Answer 2

Resposta:A)(X+5)²

X²+10x+25

B)(a+3)²

A²+6a+9

C)(4+m)²

16+8m+m²

D)(x+a)²

X²+2xa+a²

E)(3x+2)²

9x²+12x+4

F)(4ª+1)²

(4ª)²+8ª+1

4²ª+8ª+1

G)(2x+y²)²

4x²+4y²x+y⁴