Question

1-Determine os valores dos coeficientes a,b,c nas equaçoes dos 2 grau
A= 2 x ao quadrado -8x + 7=0
b= 3 x ao quadrado -7x-4=0
c =x ao quadrado = -6-0
d= -x ao quadrado=4x+9=0
e= -8x ao quadrado -x-1=0
f=4x ao quadrado -16=0
g=x ao quadrado -3x=0
h= 5x ao quadrado - 28=0
i= 6x ao quadrado =0

Answer 1

Resposta:

a) ∆ =b²-4AC

∆ =(-6)²-4(1)(-7)

∆ =36+28

∆ =64

x'=-(-6)+8/2=14/2=7

x"=-(-6)-8/2=-2/2=-1

b) ∆ =b²-4AC

∆ =(-6)²-4(7)(-1)

∆ =36+28

∆ =64

x'=-(-6)+8/2×7=14/14=1

x"=-(-6)-8/2×7=-2:2/14:2=-1/7

c) ∆ =b²-4AC

∆ =(-3)²-4(2)(-2)

∆ =9+16

∆ =25

x'=-(-3)+5/2×2=8/4=2

x"=-(-3)-5/2×2=-2:2/4:2=-1/2

d) ∆ =b²-4AC

∆ =(6)²-4(8)(-2)

∆ =36+64

∆ =100

x'=-(6)+10/2×8=4:4/16:4=1/4

x"=-(6)-10/2×8=-16:2/14:2=-8/7

e) ∆ =b²-4AC

∆ =(6)²-4(2)(-8)

∆ =36+64

∆ =100

x'=-(6)+10/2×2=4/4=1

x"=-6-10/2×2=16/4=4

f) ∆ =b²-4AC

∆ =(18)²-4(1)(17)

∆ =334-64

∆ =256

x'=-18+16/2=-2/2=-1

x"=-18-16/2=34/2=17

g) ∆ =b²-4AC

∆ =(6)²-4(1)(-7)

∆ =36+28

∆ =64

x'=-6+8/2=2/2=1

x"=-6-8/2=-14/2=-7

h) ∆ =b²-4AC

∆ =(6)²-4(7)(-1)

∆ =36+28

∆ =64

x'=-6+8/2×7=2:2/14:2=1/7

x"=-6-8/2×7=14/14=1

i) ∆ =b²-4AC

∆ =(3)²-4(2)(-2)

∆ =25

x'=-3+5/2×2=2:2/4:2=1/2

x"=-3-5/2×2=-8/4=-2

j) ∆ =b²-4AC

∆ =(-6)²-4(8)(-2)

∆ =36+64

∆ =100

x'=-(-6)+10/2×8=16/16=1

x"=-(-6)-10/2×8=-4:4/16:4=1/4

k) ∆ =b²-4AC

∆ =(-6)²-4(2)(-2)

∆ =36+16

∆ =64

x'=-(-6)+8/2×2=14:2/4:2=7/2

x"-(-6)-8/2×2=-2:2/4:2=-1/2

l) ∆ =b²-4AC

∆ =(-18)²-4(1)(17)

∆ =324-68

∆ =256

x'=-(-18)-16/2=2/2=1

x"=-(-18)+16/2=34/2=17