Question

1.Determine o valor de x de y nos pares de triângulos semelhantes


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Answer 1

$\large\boxed{\begin{array}{l}\sf a)~\rm\triangle ABC\sim\triangle A'B'C'\\\rm\dfrac{9}{3}=\dfrac{x}{6}\\\\\rm 3=\dfrac{x}{6}\\\\\rm x=3\cdot6\\\rm x=18\\\rm\dfrac{9}{3}=\dfrac{12}{y}\\\\\rm 3=\dfrac{12}{y}\\\\\rm 3y=12\\\rm y=\dfrac{12}{3}\\\\\rm y=4\end{array}}$

$\large\boxed{\begin{array}{l}\sf b)~\rm\triangle ABC\sim\triangle A'B'C'\\\rm\dfrac{x}{12}=\dfrac{4}{8}\\\\\rm\dfrac{x}{12}=\dfrac{1}{2}\\\\\rm 2x=12\\\rm x=\dfrac{12}{2}\\\\\rm x=6\\\rm\dfrac{5}{y}=\dfrac{4}{8}\\\\\rm 5y=40\\\rm y=\dfrac{40}{5}\\\\\rm y=8\end{array}}$