Question

1) determine as raizes das seguintes funções ​

Answer 1

$1-\\\\a)\frac{d}{dx}\left(x-10\right)\\\\=\frac{d}{dx}\left(x\right)-\frac{d}{dx}\left(10\right)\\\\=1-0\\\\=1\\\\b)\frac{d}{dx}\left(x+15\right)\\\\=\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(15\right)\\\\=1+0\\\\=1\\\\c)\frac{d}{dx}\left(2x-16\right)\\\\\frac{d}{dx}\left(2x-16\right)\\\\=2-0\\\\=2\\\\d) \frac{d}{dx}\left(4x+12\right)\\\\=\frac{d}{dx}\left(4x\right)+\frac{d}{dx}\left(12\right)\\\\=4+0\\\\=4\\\\e) \frac{d}{dx}\left(5x-25\right)$

$=\frac{d}{dx}\left(5x\right)-\frac{d}{dx}\left(25\right)\\\\=5-0\\\\=5$

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$2 -\\\\a) \frac{d}{dx}\left(2x-5\right)\\\\=\frac{d}{dx}\left(2x\right)-\frac{d}{dx}\left(5\right)\\\\=2-0\\\\=2\\\\b) \frac{d}{dx}\left(3x+13\right)\\\\=\frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(13\right)\\\\=3+0\\\\=3\\\\c) \frac{d}{dx}\left(3x-1\right)\\\\=\frac{d}{dx}\left(3x\right)-\frac{d}{dx}\left(1\right)\\\\=3-0\\\\=3\\\\d) \frac{d}{dx}\left(x+12\right)\\\\=\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(12\right)\\\\=1+0\\\\=1$

$e) \frac{d}{dx}\left(5x-5\right)\\\\=\frac{d}{dx}\left(5x\right)-\frac{d}{dx}\left(5\right)\\\\=5-0\\\\=5$