Question

1) Dados log 2 = 0,3010 e log 3 = 0,4771, calcule:

a) log $\frac{2}{3}$

b) log 1,5

c) log $\frac{10}{3}$

d) log 5

Answer 1

log 2/3
log 2 - log 3
0.3010 - 0.4771
−0.1761


log1,5
log 3/2
Log3 - log2
0.4771-0.3010
0.1761


Log 10/3
Log10 - Log3
1 - 0.4771
0.5229

log5
log10/2
Log10-log2
1-0.3010
0.699

Answer 2

a) log 

   log 2 - log3 =  0,3010 - 0,4771==> - 0,1761


b) log 1,5 = log 15/10 ==>log15 - log10 ==> log(3.5) - 1
 log3 + log 5 - 1==> log3 + log10/2 ==> log3 - 1 + log10 - log2
log3 - 1 + 1 - log2 ==> 0,4771 - 0,3010 ==> 0,1761 

c) log 

log 10 - log 3 ==>1 - 0,4771 ==>0,5229

d) log 5 =  log10/2 ==>  log10 - log2 ==> 1- 0,3010 ==> 0,6990