Question

1) Dados A = (2x -1) e B = (2x +1) DETERMINE:
a) $A^{2}$ - $B^{2}$
b) (A - B)$^{2}$

Answer 1

a) $( 2x-1)^{2} - (2x+1)^{2}$
$2x^{2} -2x + 1 - (2x^{2} +2x +1)$
$2x^{2} -2x + 1 -2x^{2} -2x -1 -4x b)[tex][(2x-1-(2x+1)]^{2}$
$(2x-1-2x-1)^{2} = (-2)^{2}$ = 4