Matemática, perguntado por Sabrina1234, 1 ano atrás

1- Dadas as Matrizes, A=  A=\left[\begin{array}{ccc}1&2&3\\-4&5&6\\4&6&8\end{array}\right]   B=\left[\begin{array}{ccc}-7&-8&9\\12&6&5\\8&7&4\end{array}\right] C=\left[\begin{array}{ccc}2&3&-4\\6&7&1\\2&8&7\end{array}\right]
Determine a Matriz D resultado da operação A=B-C ?


korvo: D=A+B-C é isso??
Sabrina1234: D= A+B-C , desculpe.

Soluções para a tarefa

Respondido por korvo
5
Olá Sabrina,

acho que digitou =, ao invés de, +..

D=A+B-C\\\\
D=  \left(\begin{array}{ccc}1&2&3\\-4&5&6\\4&6&8\end{array}\right)+  \left(\begin{array}{ccc}-7&-8&9\\12&6&5\\8&7&4\end{array}\right)-  \left(\begin{array}{ccc}2&3&-4\\6&7&1\\2&8&7\end{array}\right)\\\\
D=  \left(\begin{array}{ccc}1+(-7)&2+(-8)&3+9\\-4+12&5+6&6+5\\4+8&6+7&8+4\end{array}\right)-  \left(\begin{array}{ccc}2&3&-4\\6&7&1\\2&8&7\end{array}\right)

D=  \left(\begin{array}{ccc}-6&-6&12\\8&11&11\\12&13&12\end{array}\right)-  \left(\begin{array}{ccc}2&3&-4\\6&7&1\\2&8&7\end{array}\right)\\\\
D=  \left(\begin{array}{ccc}-6-2&-6-3&12-(-4)\\8-6&11-7&11-1\\12-2&13-8&12-7\end{array}\right)\\\\\\
\Large\boxed{\boxed{D=  \left(\begin{array}{ccc}-18&-9&16\\2&4&10\\10&5&5\end{array}\right)}}

Tenha ótimos estudos ;D
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